Nikon D300 sensor question

In article , adm
wrote:

Thanks. But I already know that. I want to know the actual pixel size in
microns though, as well as the true available imaging area size of the
sensor, not just the nominal size and pixel count.

it's easy to calculate.

the sensor is 23.6 x 15.8mm and produces an image of 4288 x 2848
pixels. dividing, you get 5.5 micron pixels.

"Norm Dresner" wrote in message
...
"adm" wrote in message
...
|
| "Norm Dresner" wrote in message
| ...
| "adm" wrote in message
| news | | Hi,
| |
| | Does anyone know the exact sensor (pixel area part) dimensions and
pixel
| | sizes of the sensor used in the Nikon D300? I want to try and work
out
| the
| | field of view I will get if I attach it to my telescope. (It's
| effectively
| a
| | 2500mm f/10 lens....)
| |
|
| It's 2/3 the size of a 35mm film frame which is nominally 24x36mm.
The
| dimensions of the array are 4288x2848 which your camera would tell you
if
| you asked it to.
|
| Norm
|
| Thanks. But I already know that. I want to know the actual pixel size in
| microns though, as well as the true available imaging area size of the
| sensor, not just the nominal size and pixel count.

You can't do simple arithmetic?

2/3 x 24mm / 2848 is the vertical dimension of the pixel.

Norm

What about the gaps between the individual photosites - what size are they?

The actual individual photosite size is going to be somewhat smaller than
simply taking the sensor size and dividing it by resolutiuon.

As an example, if I look at a Sony ExView HAD CCD (ICX285AQ) chip, the
sensor dimension is 10.2 x 8.3mm with a resolution of 1434 x 1050 pixels to
give a resolution of c.1.5M, yet the pixel size is 6.45u x 6.45u

If I just divide the size of the sensor by the resolution, it gives me 1581
pixels x 1286 pixels, or conversely a 7.11u x 7.9u pixel.

So in reality, the actual photosite size is significantly smaller than the
result obtained by dividing the outside dimension of the sensor by the
number of pixels.

Anyway, no big deal and I don't want to argue about it.....I was interested
in the actual size of the photosites for the sakes of comparison and maybe
using the terminology pixel wasn't the best way to go about it. I can get my
FOV and arcsec/pixel number with the simple arithmetic approach (0.46
arcsec/pixel, 32.4 x 21.7 arcmin FOV)

In article , adm
wrote:

What about the gaps between the individual photosites - what size are they?

the microlenses give you close to a 100% fill factor. it's not really
significant.

On Wed, 16 Apr 2008 12:28:23 GMT, "Norm Dresner" wrote:
: "adm" wrote in message
: ...
: |
: | "Norm Dresner" wrote in message
: | ...
: | "adm" wrote in message
: | news : | | Hi,
: | |
: | | Does anyone know the exact sensor (pixel area part) dimensions and pixel
: | | sizes of the sensor used in the Nikon D300? I want to try and work out
: | | the field of view I will get if I attach it to my telescope. (It's
: | effectively
: | a
: | | 2500mm f/10 lens....)
: | |
: |
: | It's 2/3 the size of a 35mm film frame which is nominally 24x36mm. The
: | dimensions of the array are 4288x2848 which your camera would tell you
: | if you asked it to.
: |
: | Norm
: |
: | Thanks. But I already know that. I want to know the actual pixel size in
: | microns though, as well as the true available imaging area size of the
: | sensor, not just the nominal size and pixel count.
:
: You can't do simple arithmetic?
:
: 2/3 x 24mm / 2848 is the vertical dimension of the pixel.

If you don't know the answer, why don't you just say so, instead of insulting
the questioner? There's no shame in being ignorant, unless you are and pretend
you're not.

Bob

"Robert Coe" wrote in message
...
| On Wed, 16 Apr 2008 12:28:23 GMT, "Norm Dresner" wrote:
| : "adm" wrote in message
| : ...
| : |
| : | "Norm Dresner" wrote in message
| : | ...
| : | "adm" wrote in message
| : | news | : | | Hi,
| : | |
| : | | Does anyone know the exact sensor (pixel area part) dimensions and
pixel
| : | | sizes of the sensor used in the Nikon D300? I want to try and work
out
| : | | the field of view I will get if I attach it to my telescope. (It's
| : | effectively
| : | a
| : | | 2500mm f/10 lens....)
| : | |
| : |
| : | It's 2/3 the size of a 35mm film frame which is nominally 24x36mm.
The
| : | dimensions of the array are 4288x2848 which your camera would tell
you
| : | if you asked it to.
| : |
| : | Norm
| : |
| : | Thanks. But I already know that. I want to know the actual pixel size
in
| : | microns though, as well as the true available imaging area size of the
| : | sensor, not just the nominal size and pixel count.
| :
| : You can't do simple arithmetic?
| :
| : 2/3 x 24mm / 2848 is the vertical dimension of the pixel.
|
| If you don't know the answer, why don't you just say so, instead of
insulting
| the questioner? There's no shame in being ignorant, unless you are and
pretend
| you're not.
|
| Bob

The size of the pixel is given by the formula I presented!
Norm

Focus wrote:
"OldBoy" wrote in message

Read this first:
http://www.astrosurf.com/buil/nikon_test/test.htm

Ah, yes, Nikons' "RAW", nicely "de-starred".

Finally found something. If Canon can't go *in* space, at least they can
stare at it ;-)

And how they can!
Found 10 planets in 6 months, too! (And I am quite sure they
repair these delaminating lenses avery half hour, Rita!)

http://www.superwasp.org/

Beat that, Nikon! :-

-Wolfgang